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DomnikaMaksimova
@DomnikaMaksimova
July 2022
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HEEEELLLLLLLLLLLLPPPPPPPPP (ПОДРОБНОЕ РЕШЕНИЕ)
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ВладимирБ
Verified answer
Решение смотри в приложении
1 votes
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sedinalana
Verified answer
1
(5x+4)/(x-3) -4<0
(5x+4-4x+12)/(x-3)<0
(x+16)/(x-3)<0
x=-16 x=3
+ _ +
----------------(-16)---------------(3)----------------
x∈(-16;3)
2
2/(x-4)-1<0
(2-x+4)/(x-4)<0
(6-x)/(x-4)<0
(x-6)/(x-4)>0
x=6 x=4
+ _ +
----------------(4)---------------(6)----------------
x∈(-∞;4) U (6;∞)
3
2/(x+3)-4<0
(2-4x-12)/(x+3)<0
(-4x-10)/(x+3)<0
(4x+10)/(x+3)>0
x=-2,5 x=-3
+ _ +
----------------(-3)---------------(-2,5)----------------
x∈(-∞;-3) U (-2,5;∞)
0 votes
Thanks 0
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Answers & Comments
Verified answer
Решение смотри в приложенииVerified answer
1(5x+4)/(x-3) -4<0
(5x+4-4x+12)/(x-3)<0
(x+16)/(x-3)<0
x=-16 x=3
+ _ +
----------------(-16)---------------(3)----------------
x∈(-16;3)
2
2/(x-4)-1<0
(2-x+4)/(x-4)<0
(6-x)/(x-4)<0
(x-6)/(x-4)>0
x=6 x=4
+ _ +
----------------(4)---------------(6)----------------
x∈(-∞;4) U (6;∞)
3
2/(x+3)-4<0
(2-4x-12)/(x+3)<0
(-4x-10)/(x+3)<0
(4x+10)/(x+3)>0
x=-2,5 x=-3
+ _ +
----------------(-3)---------------(-2,5)----------------
x∈(-∞;-3) U (-2,5;∞)