Хееелп!:) log2(3^x-1)+log2(3^x-2)=1. Created by youlia. algebra-ru

Хееелп!:) log2(3^x-1)+log2(3^x-2)=1...

July 2022 1 0 Report

Хееелп!:) log2(3^x-1)+log2(3^x-2)=1

Answers & Comments

Akula17 3^x -1 =a
3^x-2 = b
log2 a + log2b = 1
log2 ab=1
(3^x-1)(3^x-2)=2
3^x = t
(t-1)(t-2) =2
t^2 -3t+1=0
D=(-3)^2 - 4 *1*1=9 - 4 = 5
√D=√5
t 1= 3+√5 / 2
t 2 = 3 -√5 / 2

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youlia Спасибо большое)

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