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Leto71
@Leto71
April 2021
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Хееелп. Помогите решить неравенства
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oganesbagoyan
Verified answer
Task/25777998
--------------------
3^(2x-1) -3^ (2x-3) < 8/3;
3^(2x -3)* ( 3² -1) < 8/3;
3^(2x -3)* 8 <
8/3 ;
3^(2x -3) < 3
⁻¹
2x -3 < -1 ;
x < 1.
* * * x∈ (-∞ ; 1). * * *
----------
(1/5) ^(3x +4) +(1/5) ^(3x +5) > 6
(1/5) ^(3x+5)* ( (1/5)⁻¹ + 1) >6 ;
(1/5) ^(3x+5)* ( 5 + 1) >6 ;
(1/5) ^(3x+5) > (1/5)
⁰ ; * * * 0 <1/5 <1 * * *
3x+5 < 0 ;
x <-3/5 .
* * * x∈ (- ∞ ; 0,6) . * * *
----------
(0,3) ^(6x -1) - (0,3) ^(6x) ≥ 0,7 ;
(0,3) ^(6x -1) *(1 - 0,3) ≥
0,7 ;
(0,3) ^(6x -1) *0,7 ≥ 0,7 ;
(0,3) ^(6x -1) ≥ (0,3)⁰ ; * * * 0< 0,3 <1 * * *
6x -1 ≤ 0 ;
x ≤ 1/6 . * * * x∈ (-∞ ; 1/6]. * * *
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Answers & Comments
Verified answer
Task/25777998--------------------
3^(2x-1) -3^ (2x-3) < 8/3;
3^(2x -3)* ( 3² -1) < 8/3;
3^(2x -3)* 8 < 8/3 ;
3^(2x -3) < 3⁻¹
2x -3 < -1 ;
x < 1. * * * x∈ (-∞ ; 1). * * *
----------
(1/5) ^(3x +4) +(1/5) ^(3x +5) > 6
(1/5) ^(3x+5)* ( (1/5)⁻¹ + 1) >6 ;
(1/5) ^(3x+5)* ( 5 + 1) >6 ;
(1/5) ^(3x+5) > (1/5)⁰ ; * * * 0 <1/5 <1 * * *
3x+5 < 0 ;
x <-3/5 . * * * x∈ (- ∞ ; 0,6) . * * *
----------
(0,3) ^(6x -1) - (0,3) ^(6x) ≥ 0,7 ;
(0,3) ^(6x -1) *(1 - 0,3) ≥ 0,7 ;
(0,3) ^(6x -1) *0,7 ≥ 0,7 ;
(0,3) ^(6x -1) ≥ (0,3)⁰ ; * * * 0< 0,3 <1 * * *
6x -1 ≤ 0 ;
x ≤ 1/6 . * * * x∈ (-∞ ; 1/6]. * * *