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lubavuuuushka
@lubavuuuushka
July 2022
1
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Heelp)
2sin^2x-2cos^2x-√3=0
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safin1ilya
Verified answer
2sin²x-2cos²x-√3=0
2(sin²x-cos²x)=√3 |:2
sin²x-cos²x=√3/2|•(-1)
cos²x-sin²x=-√3/2
cos2x=-√3/2
2x=±(п-arccos√3/2)+2пn,n€z
2x=±5п/6+2пn,n€z
x=±5п/12+пn,n€z
18 votes
Thanks 39
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Answers & Comments
Verified answer
2sin²x-2cos²x-√3=02(sin²x-cos²x)=√3 |:2
sin²x-cos²x=√3/2|•(-1)
cos²x-sin²x=-√3/2
cos2x=-√3/2
2x=±(п-arccos√3/2)+2пn,n€z
2x=±5п/6+2пn,n€z
x=±5п/12+пn,n€z