2Cu + O2 = 2CuO
n = m/M
M(Cu) = 64
n(Cu) = 20/64 = 0.3
По ур. реакции n(Cu) = n(CuO) = 0.3 моль
m = M*n
M (CuO) = 64+16 = 80
m(CuO) = 0.3 * 80 = 24 г.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2Cu + O2 = 2CuO
n = m/M
M(Cu) = 64
n(Cu) = 20/64 = 0.3
По ур. реакции n(Cu) = n(CuO) = 0.3 моль
m = M*n
M (CuO) = 64+16 = 80
m(CuO) = 0.3 * 80 = 24 г.