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79206566122
@79206566122
July 2022
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oganesbagoyan
Verified answer
1) <ABC
=<AOC/2 =120°/2
=60
°
.
2) <ABC
=(360°-120°)/2=240°2
=120
°
.
3) <ABC
=дуга(AFC)/2 =(360° -дуга(ABC))/2 =(360° -140°)/2 =220°/2
=110°
.
4) <AFC
= <ABC
=80
°.
X---X
1) <ADC
=<ABC
=50
°.
2) <ADC
= <ABC
=120
°.
3) <ADC
=180° - <ABC =180° -70°
=110°.
4) <CDB=180
° -(60° +80°) =40°.
по рисунке <ADC больше 20° но меньше 40°.
2 votes
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Answers & Comments
Verified answer
1) <ABC =<AOC/2 =120°/2=60°.2) <ABC =(360°-120°)/2=240°2=120° .
3) <ABC =дуга(AFC)/2 =(360° -дуга(ABC))/2 =(360° -140°)/2 =220°/2 =110°.
4) <AFC = <ABC =80°.
X---X
1) <ADC =<ABC =50°.
2) <ADC = <ABC =120°.
3) <ADC =180° - <ABC =180° -70° =110°.
4) <CDB=180° -(60° +80°) =40°.
по рисунке <ADC больше 20° но меньше 40°.