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nurullina18
@nurullina18
August 2022
1
3
Report
х(х+2у)+у(у-1)=2х-1
3х-у-2х^2-4ху=4+2у^2
решите систему уравнений...
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Answers & Comments
svyaz0295
X^2+2xy+y^2-y-2x+1=0
3x-y-2x^2-4xy-2y^2-4=0
(x+y)^2-y-2x+1=0
3x-y-2(x^2+2xy+y^2)-4=0
(x+y)^2-y-2x+1=0
3x-y-2(x+y)^2-4=0
(x+y)^2=y
y-y-2x+1=0
3x-y-2y-4=0
-2x=-1
3x-3y-4=0
x=0.5
3(x-y)=4
x-y=4
x=0.5
x=12
не знаю,так или нет
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Answers & Comments
3x-y-2x^2-4xy-2y^2-4=0
(x+y)^2-y-2x+1=0
3x-y-2(x^2+2xy+y^2)-4=0
(x+y)^2-y-2x+1=0
3x-y-2(x+y)^2-4=0
(x+y)^2=y
y-y-2x+1=0
3x-y-2y-4=0
-2x=-1
3x-3y-4=0
x=0.5
3(x-y)=4
x-y=4
x=0.5
x=12
не знаю,так или нет