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DimkO72rus
@DimkO72rus
November 2021
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Химики,СОС!:D.
Запишите уравнения реакций ионного обмена(полные и сокращенные),происходящих между растворами веществ,формулы которых приведены ниже.
1.NaOH+CuSO4
2.HNO3+Ca(OH)2
3.K2CO3+HCL
4.KCL+NaNO3
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dima6klon
Verified answer
1. 2NaOH+CuSO₄=Cu(OH)₂+Na₂SO₄
2Na⁺+2OH⁻+Cu²⁺+SO₄²⁻=Cu(OH)₂+2Na⁺+SO₄²⁻
2OH⁻+Cu²⁺=Cu(OH)₂
2. 2HNO₃+Ca(OH)₂=Ca(NO₃)₂+2H₂O
2H⁺+2NO₃⁻+Ca(OH)₂=Ca²⁺+2NO₃⁻+2H₂O
2H⁺+Ca(OH)₂=Ca²⁺+2H₂O
Если рысписывать гидроксид кальция, то:
2H⁺+2NO₃⁻+Ca²⁺+2OH⁻=Ca²⁺+2NO₃⁻+2H₂O
2H⁺+2OH⁻=2H₂O
3. K₂CO₃+2HCl=2KCl+CO₂+H₂O
2K⁺+CO₃²⁻+2H⁺+2Cl⁻=2K⁺+2Cl⁻+CO₂+H₂O
CO₃²⁻+2H⁺=CO₂+H₂O
4. KCl+NaNO₃≠
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julyap
Verified answer
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Answers & Comments
Verified answer
1. 2NaOH+CuSO₄=Cu(OH)₂+Na₂SO₄2Na⁺+2OH⁻+Cu²⁺+SO₄²⁻=Cu(OH)₂+2Na⁺+SO₄²⁻
2OH⁻+Cu²⁺=Cu(OH)₂
2. 2HNO₃+Ca(OH)₂=Ca(NO₃)₂+2H₂O
2H⁺+2NO₃⁻+Ca(OH)₂=Ca²⁺+2NO₃⁻+2H₂O
2H⁺+Ca(OH)₂=Ca²⁺+2H₂O
Если рысписывать гидроксид кальция, то:
2H⁺+2NO₃⁻+Ca²⁺+2OH⁻=Ca²⁺+2NO₃⁻+2H₂O
2H⁺+2OH⁻=2H₂O
3. K₂CO₃+2HCl=2KCl+CO₂+H₂O
2K⁺+CO₃²⁻+2H⁺+2Cl⁻=2K⁺+2Cl⁻+CO₂+H₂O
CO₃²⁻+2H⁺=CO₂+H₂O
4. KCl+NaNO₃≠
Verified answer