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zheniaze
@zheniaze
July 2022
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Химия 10-11 класс
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kekun4ick
Verified answer
1) C + 2H2 (Pt, 600°C) = CH4
CH4 + Cl2 (hv) = CH3Cl + HCl
2CH3Cl + 2Na (t) = 2NaCl + H3C—CH3
H3C—CH3 + Cl2 (hv) = H3C—CH2Cl + HCl
2) CH3COONa(тв.) + NaOH(тв.) (t) = Na2CO3 + CH4
CH4 + Br2 (hv) = CH3Br + HBr
2CH3Br + 2Na (t) = 2NaBr + H3C—CH3
2H3C—CH3 + 7O2 (t) = 4CO2 + 6H2O
CO2 + C (t) = 2CO
3) Al4C3 + 12HCl = 4AlCl3 + 3CH4
2CH4 (1500°C) = HC≡CH + 3H2
4) C3H8 + Br2 (hv) = H3C—CH(Br)—CH3 + HBr
2H3C—CH(Br)—CH3 + 2Na (t) = 2NaBr + H3C-CH(CH3)-CH(CH3)-CH3
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Answers & Comments
Verified answer
1) C + 2H2 (Pt, 600°C) = CH4CH4 + Cl2 (hv) = CH3Cl + HCl
2CH3Cl + 2Na (t) = 2NaCl + H3C—CH3
H3C—CH3 + Cl2 (hv) = H3C—CH2Cl + HCl
2) CH3COONa(тв.) + NaOH(тв.) (t) = Na2CO3 + CH4
CH4 + Br2 (hv) = CH3Br + HBr
2CH3Br + 2Na (t) = 2NaBr + H3C—CH3
2H3C—CH3 + 7O2 (t) = 4CO2 + 6H2O
CO2 + C (t) = 2CO
3) Al4C3 + 12HCl = 4AlCl3 + 3CH4
2CH4 (1500°C) = HC≡CH + 3H2
4) C3H8 + Br2 (hv) = H3C—CH(Br)—CH3 + HBr
2H3C—CH(Br)—CH3 + 2Na (t) = 2NaBr + H3C-CH(CH3)-CH(CH3)-CH3