дано
V(H2) = 56 mL = 0.056 L
------------------------------------
m(C2H5OH)-?
2C2H5OH+2Na-->2C2H5ONa+H2
n(H2) = V(H2) / Vm = 0.056 / 22.4 = 0.0025 mol
2n(C2H5OH) = n(H2)
n(C2H5OH) = 2*0.0025 = 0.005 mol
M(C2H5OH) = 46 g/mol
m(C2H5OH) = n*M = 0.005 * 46 = 0.23 g
ответ 0.23 г
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дано
V(H2) = 56 mL = 0.056 L
------------------------------------
m(C2H5OH)-?
2C2H5OH+2Na-->2C2H5ONa+H2
n(H2) = V(H2) / Vm = 0.056 / 22.4 = 0.0025 mol
2n(C2H5OH) = n(H2)
n(C2H5OH) = 2*0.0025 = 0.005 mol
M(C2H5OH) = 46 g/mol
m(C2H5OH) = n*M = 0.005 * 46 = 0.23 g
ответ 0.23 г