1. 2NaBr + Cl2 = 2NaCl + Br2
2K + Br2 = 2KBr
2. 297кДж - 32г
118.8 кДж - х= 12.8г
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Answers & Comments
1. 2NaBr + Cl2 = 2NaCl + Br2
2K + Br2 = 2KBr
2. 297кДж - 32г
118.8 кДж - х= 12.8г