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Дано:m (Cu(OH)₂) = 49 гНайти:n (Cu(OH)₂) - ?Решение:M (Cu(OH)₂) = Ar(Cu) + 2*Ar(O) + 2*Ar(H)M (Cu(OH)₂) = 64 + 2*16 + 2*1 = 98 г/моль мольОтвет: 0,5 моль.

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LemiLumi

Дано:

m (Cu(OH)₂) = 49 г

Найти:

n (Cu(OH)₂) - ?

Решение:

$n = \frac{m}{M}$

M (Cu(OH)₂) = Ar(Cu) + 2*Ar(O) + 2*Ar(H)

M (Cu(OH)₂) = 64 + 2*16 + 2*1 = 98 г/моль

$n (Cu(OH)_{2}) = \frac{49}{98} = 0,5$ моль

Ответ: 0,5 моль.

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Answers & Comments

Дано:

Найти:

Решение:

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