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Ritu4
@Ritu4
September 2021
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химия, решите 2 номера
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аДРОБин
2.
хлорная кислота - HClO4
M(HClO4)=100.5, М(Сl)=35.5
w(Cl)=35.5/100.5=0.3532(35.32%)
хлорватистая кислота - HClO
M(HClO)=52.5
w(Cl)=35.5/52.5=0.6762(67.62%)
3.
n=m/M, M(Zn)=65
n(Zn)=30/65=0.46(моль).
4.
n=N/N(a), N=nxN(a), N(a)=6.02*10(23)
n(Cl)=30/35.5=0.845(моль).
N=0.845x6.02*10(23)=5.087*10(23) молекул
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Answers & Comments
хлорная кислота - HClO4
M(HClO4)=100.5, М(Сl)=35.5
w(Cl)=35.5/100.5=0.3532(35.32%)
хлорватистая кислота - HClO
M(HClO)=52.5
w(Cl)=35.5/52.5=0.6762(67.62%)
3.
n=m/M, M(Zn)=65
n(Zn)=30/65=0.46(моль).
4.
n=N/N(a), N=nxN(a), N(a)=6.02*10(23)
n(Cl)=30/35.5=0.845(моль).
N=0.845x6.02*10(23)=5.087*10(23) молекул