Ответ:
дано
W(Cr) = 68,4 %
-----------------------------
CrxOy - ?
W(O) = 100% - W(Cr) = 100- 68,4 = 31.6%
m(Cr) = 68,4 g Ar(Cr) = 52 g/mol
m(O) = 31.6 g Ar(O) = 16 g/mol
Crx : Oy = 68.4 / 52 : 31.6 / 16 = 1.3 : 1.9 = 1: 1.5 = 2:3
Cr2O3
ответ :Cr2O3
Объяснение:
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Answers & Comments
Ответ:
дано
W(Cr) = 68,4 %
-----------------------------
CrxOy - ?
W(O) = 100% - W(Cr) = 100- 68,4 = 31.6%
m(Cr) = 68,4 g Ar(Cr) = 52 g/mol
m(O) = 31.6 g Ar(O) = 16 g/mol
Crx : Oy = 68.4 / 52 : 31.6 / 16 = 1.3 : 1.9 = 1: 1.5 = 2:3
Cr2O3
ответ :Cr2O3
Объяснение: