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Саша110901
@Саша110901
July 2022
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(х+у)^2+4у^2+4у+3>0 докажите неравенство пожалуйста срочно
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ВладимирБ
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(х+у)^2+4у^2+4у+3=(х+у)^2+4у^2+4у+1+2=(х+у)^2+(2y+1)^2+2>0
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(х+у)^2+4у^2+4у+3=(х+у)^2+4у^2+4у+1+2=(х+у)^2+(2y+1)^2+2>0