Ответ:

а)

[tex] {x}^{2} - 49 = 0[/tex]

[tex] {x}^{2} + 0x - 49 = 0[/tex]

[tex] {x}^{2} + 0x + ( - 49) = 0[/tex]

[tex]p = 0.q = - 49[/tex]

[tex]x = - \frac{0}{2} ± \sqrt{ {( \frac{0}{2}) }^{2} - ( - 49) }[/tex]

[tex]x = - 0± \sqrt{ {0}^{2} + 49} [/tex]

[tex]x = - 0± \sqrt{0 + 49} [/tex]

[tex]x = - 0± \sqrt{49} [/tex]

[tex]x = - 0± \sqrt{ {7}^{2} } [/tex]

[tex]x = - 0±7[/tex]

[tex]x = ±7[/tex]

[tex]x = 7 \\ x = - 7[/tex]

[tex]{x}_{1}=-7, {x}_{2}=7[/tex]

б)

[tex] {x}^{2} - 144 = 0[/tex]

[tex] {x}^{2} + 0x - 144 = 0[/tex]

[tex] {x}^{2} + 0x + ( - 144) = 0[/tex]

[tex]p = 0.q = - 144[/tex]

[tex]x = - \frac{ 0}{2} ± \sqrt{ {( \frac{0}{2} )}^{2} - ( - 144) } [/tex]

[tex]x = - 0± \sqrt{ {0}^{2} + 144} [/tex]

[tex]x = - 0± \sqrt{0 + 144} [/tex]

[tex]x = - 0± \sqrt{144} [/tex]

[tex]x = - 0± \sqrt{ {12}^{2} } [/tex]

[tex]x = - 0±12[/tex]

[tex]x = ±12[/tex]

[tex]x = 12 \\ x = - 12[/tex]

[tex]x_{1} = - 12. x_{2} = 12[/tex]

в)

[tex] {x}^{2} = 0.49[/tex]

[tex] {x}^{2} = \frac{49}{100} [/tex]

[tex] {x}^{2} - \frac{49}{100} = \frac{49}{100} - \frac{49}{100} [/tex]

[tex] {x}^{2} - \frac{49}{100} = 0[/tex]

[tex] {x}^{2} + 0x - \frac{49}{100} = 0[/tex]

[tex] {x}^{2} + 0x + ( - \frac{49}{100} ) = 0[/tex]

[tex]p = 0.q = - \frac{49}{100} [/tex]

[tex]x = - \frac{0}{2} ± \sqrt{ {( \frac{0}{2} )}^{2} - ( - \frac{49}{100}) } [/tex]

[tex]x = - 0± \sqrt{ {0}^{2} + \frac{49}{100} } [/tex]

[tex]x = ± \sqrt{0 + \frac{49}{100} } [/tex]

[tex]x = ± \sqrt{ \frac{49}{100} } [/tex]

[tex]x = ± \frac{ \sqrt{49} }{ \sqrt{100} } [/tex]

[tex]x = ± \frac{ \sqrt{ {7}^{2} } }{ \sqrt{ {10}^{2} } } [/tex]

[tex]x = ± \frac{7}{10} [/tex]

[tex]x = \frac{7}{10} \\ x = - \frac{7}{10} [/tex]

[tex]x_{1} = - \frac{7}{10} . x_{2} = \frac{7}{10} [/tex]