Ответ: W(7H2O) = 45,32%
Mr(FeSO4×7H2O) = 152 + 126 = 278
Mr(7H2O) = 18×7 = 126
W(7H2O) = (126 : 278) × 100% = 45,32%
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Ответ: W(7H2O) = 45,32%
Mr(FeSO4×7H2O) = 152 + 126 = 278
Mr(7H2O) = 18×7 = 126
W(7H2O) = (126 : 278) × 100% = 45,32%