August 2021 0 6 Report
Пусть AB= 6см, AD= 10см, /_ А= 30*. Так как диагональ параллелограмма делит его на два (равнобедренных/разных/разносторонних треугольника), то /_\ ABC=/_\ (?) и поэтому Sabc=S(?)=(?) • Sabcd
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