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kafkaluca
@kafkaluca
July 2022
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Имеется 4 г смеси P2O5 и K3PO4, в которой массовая доля фосфора равна 21,88%. Определите массы веществ в исходной смеси.
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DJToxa
Verified answer
W(p)=62*100%/142=44(p2o5)
w(p)=31*100%/212=15%(k3po4)
w(p)=21.88=22
(44-22)+(22-15)=29
m(k3po4)=(44-22)*4/29=3г
m(p2o5)=(22-15)*4/29=1г
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Verified answer
W(p)=62*100%/142=44(p2o5)w(p)=31*100%/212=15%(k3po4)
w(p)=21.88=22
(44-22)+(22-15)=29
m(k3po4)=(44-22)*4/29=3г
m(p2o5)=(22-15)*4/29=1г