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vchppo
@vchppo
July 2022
2
21
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используя тождество sin^2a + cos^2a =1 упростите выражение:
1)sin^2a-1
2)(sinа +cosа)^2+(sinа -cosа)^2
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sedinalana
Verified answer
Sin²a+cos²a=1
sin²a=1-cos²a
1)sin²a-1=1-cos²a-1=-cos²a
2)(sina+cosa)²+(sina-cosa)²=sin²a+2sinacosa+cos²a+=sin²a-2sinacosa+cos²a=
1+1=2
19 votes
Thanks 52
yugolovin
Verified answer
1) sin^2 a -1= 1-cos^2 a -1 = - cos^2 a
2) (sin a + cos a)^2 + (sin a - cos a)^2=
sin^2 a+2 sin a· cos a + cos^2 a+ sin^2 a - 2sin a · cos a + cos^2 a = 2
16 votes
Thanks 29
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Answers & Comments
Verified answer
Sin²a+cos²a=1sin²a=1-cos²a
1)sin²a-1=1-cos²a-1=-cos²a
2)(sina+cosa)²+(sina-cosa)²=sin²a+2sinacosa+cos²a+=sin²a-2sinacosa+cos²a=
1+1=2
Verified answer
1) sin^2 a -1= 1-cos^2 a -1 = - cos^2 a2) (sin a + cos a)^2 + (sin a - cos a)^2=
sin^2 a+2 sin a· cos a + cos^2 a+ sin^2 a - 2sin a · cos a + cos^2 a = 2