October 2021 0 8 Report
Исследовать систему на совместность | x1-3x2+4x3+2x4=1,
| 2x1+4x2-3x3+3x4=-1,
| 3x1+x2+2x3-x4=0,
| 12x1+4x2+7x3+2x4=0.
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