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belfeek
@belfeek
July 2022
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известно, а+в=7, ав=12. найти значение выражения (а-в)^2
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45ghhh
A+b=7
ab=12
a=7-b
b(7-b)=12
a=7-b
7b-b²-12=0
b² -7b+12=0
D=7²-4*12=1
b1=(7-1)/2=3
b2=(7+1)/2=4
b1=3 b2=4
a1=7-3 a2=7-4
b1=3 b2=4
a1=4 a2=3
(a-b)²
(a1-b1)²=(4-3)(4-3)=1
(a2-b2)²=(3-4)(3-4)=1
(a-b)²=1
2 votes
Thanks 1
гюйс
Verified answer
A=4
b=3
a+b=7
a*b=12
(a-b)^2=(4-3)^2=1^2=1
1 votes
Thanks 1
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Answers & Comments
ab=12
a=7-b
b(7-b)=12
a=7-b
7b-b²-12=0
b² -7b+12=0
D=7²-4*12=1
b1=(7-1)/2=3
b2=(7+1)/2=4
b1=3 b2=4
a1=7-3 a2=7-4
b1=3 b2=4
a1=4 a2=3
(a-b)²
(a1-b1)²=(4-3)(4-3)=1
(a2-b2)²=(3-4)(3-4)=1
(a-b)²=1
Verified answer
A=4b=3
a+b=7
a*b=12
(a-b)^2=(4-3)^2=1^2=1