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Umbrellа5
@Umbrellа5
June 2022
2
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Известно, что 2(а+1)(в+1)=(а+в)(а+в+2). Найдите а^2+в^2.
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miron2077
Verified answer
Решение в приложении
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Thanks 2
Averor
2(а+1)(в+1)=(а+в)(а+в+2)
2ab+2a+2b+2=a^2+ab+2a+ab+b^2+2b
2ab+2a+2b+2-a^2-ab-2a-ab-b^2-2b=0
-a^2-b^2=-2
a^2+b^2=2
1 votes
Thanks 2
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Verified answer
Решение в приложении2ab+2a+2b+2=a^2+ab+2a+ab+b^2+2b
2ab+2a+2b+2-a^2-ab-2a-ab-b^2-2b=0
-a^2-b^2=-2
a^2+b^2=2