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master0628
@master0628
July 2022
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Известно, что уравнение x^2+mx+6=0 имеет корни x1 и x2. Выразите (x1-x2)^2 через m.
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koblandy1
Х1+х2=-m, x1*x2=6
(x1+x2)^2=m^2;
x1^2+x2^2=m^2-2x1*x2=m^2-12;ответ (x1-x2)^2= x1^2+x2^2-2*x1*x2= m^2-12-2*6=m^2-24;
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Answers & Comments
(x1+x2)^2=m^2;
x1^2+x2^2=m^2-2x1*x2=m^2-12;ответ (x1-x2)^2= x1^2+x2^2-2*x1*x2= m^2-12-2*6=m^2-24;