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July 2022
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Известно: x=4+2t+t^2
m=50 кг
t=20с
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jakha9696
X=4+2t+t^2=4+2*20+20^2=4+40+400=444 м
x=at^2/2 a=2м/с^2
A=FS=mas=50*2*444=44400Ч=4.44кЧ
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Answers & Comments
x=at^2/2 a=2м/с^2
A=FS=mas=50*2*444=44400Ч=4.44кЧ