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poty210Sanek
@poty210Sanek
June 2022
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К 350 г 2.5% раствора поваренной соли добавили 110 вещества Определите массовую долю вещества в полученном растворе
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mrvladimir2
Verified answer
M'(NaCl) = 350 г*0,025 = 8,75 г
m"(NaCl) = 8.75 г + 110 г = 118,75 г
m"(p-pa NaCl) = 350 г + 110 г = 460 г
ω"(NaCl) = 118,75 г/460 г = 0,2582 или 25,82%
Ответ: 25,82%
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Answers & Comments
Verified answer
M'(NaCl) = 350 г*0,025 = 8,75 гm"(NaCl) = 8.75 г + 110 г = 118,75 г
m"(p-pa NaCl) = 350 г + 110 г = 460 г
ω"(NaCl) = 118,75 г/460 г = 0,2582 или 25,82%
Ответ: 25,82%