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pahan144
@pahan144
July 2022
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Изменение энтропии при изобарическом нагревании азота от 0° С до 125° равно ΔS = 39 Дж/К. Чему равна масса азота?
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fatt52
Verified answer
I=5 ΔS=39 Дж/К T1=273 K T2=398 K M=0.028 кг/моль (N2) m=?
===
p=const
dQ=v*Cp*dT
Cp=(i+2)*R/2=(5+2)*8.31/2=29
Интегрируем
ΔS=(m/M)*Cp*ln(T2/T1)
m=ΔS*M/(Cp*ln(T2/T1))=39*0.028/(29*0.377)=0.1 кг (100 г)
==================================================
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Answers & Comments
Verified answer
I=5 ΔS=39 Дж/К T1=273 K T2=398 K M=0.028 кг/моль (N2) m=?===
p=const
dQ=v*Cp*dT
Cp=(i+2)*R/2=(5+2)*8.31/2=29
Интегрируем
ΔS=(m/M)*Cp*ln(T2/T1)
m=ΔS*M/(Cp*ln(T2/T1))=39*0.028/(29*0.377)=0.1 кг (100 г)
==================================================