А (-3, 6)
6 = k(-3) + 2
6 = -3k + 2
3k = 4
k = 4/3
D (1/3, 3)
3 = k(1/3) + 2
3 = k/3 + 2
k/3 = 1
k = 3
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Answers & Comments
А (-3, 6)
6 = k(-3) + 2
6 = -3k + 2
3k = 4
k = 4/3
D (1/3, 3)
3 = k(1/3) + 2
3 = k/3 + 2
k/3 = 1
k = 3