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@Gvozdsrs
July 2022
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K2Cr2O7+NaOH=K2CrO4+H2O+Na2CrO4 какое ионное уравнение?
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Alhimica
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K2Cr2O7+2NaOH=K2CrO4+H2O+Na2CrO4
2K(+)+Cr2O7(2-)+2Na(+)+2OH(-)=2K(+)+CrO4(2-)+H2O+2Na(+)+CrO4(2-)
Cr2O7(2-)+2OH(-)=CrO4(2-)+H2O+CrO4(2-)
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K2Cr2O7+2NaOH=K2CrO4+H2O+Na2CrO42K(+)+Cr2O7(2-)+2Na(+)+2OH(-)=2K(+)+CrO4(2-)+H2O+2Na(+)+CrO4(2-)
Cr2O7(2-)+2OH(-)=CrO4(2-)+H2O+CrO4(2-)