Ответ :ω(О) ≈ 30,33%.
Объяснение :
Mᵣ(K₂[Zn(OH)₄]) = 2Aᵣ(K) + Aᵣ(Zn) + 4Aᵣ(O) + 4Aᵣ(H) = 2*39 + 65 + 4*16 + 4*1 = 78 + 65 + 64 + 4 = 211.ω(О) = 4*Aᵣ(O) : Mᵣ(K₂[Zn(OH)₄]) = 4*16 : 211 = 64 : 211 ≈ 30,33%.#SPJ1
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Ответ :
ω(О) ≈ 30,33%.
Объяснение :
Mᵣ(K₂[Zn(OH)₄]) = 2Aᵣ(K) + Aᵣ(Zn) + 4Aᵣ(O) + 4Aᵣ(H) = 2*39 + 65 + 4*16 + 4*1 = 78 + 65 + 64 + 4 = 211.
ω(О) = 4*Aᵣ(O) : Mᵣ(K₂[Zn(OH)₄]) = 4*16 : 211 = 64 : 211 ≈ 30,33%.
#SPJ1