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kapitanova05
@kapitanova05
August 2022
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как делать : b:(38x-95)=7 при b -133
и ещё (6x-d)*8=104 при d=29
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tatianagri2013
b:(38x-95)=7 при b -133
133:(38х-95)=7
38х-95=133:7
38х-95=19
38х=19+95
38х=114
х=114:38
х=3
(6x-d)*8=104 при d=29
(6х-29)*8=104
6х-29=104:8
6х-29=13
6х=13+29
6х=42
х=42:6
х=7
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Answers & Comments
133:(38х-95)=7
38х-95=133:7
38х-95=19
38х=19+95
38х=114
х=114:38
х=3
(6x-d)*8=104 при d=29
(6х-29)*8=104
6х-29=104:8
6х-29=13
6х=13+29
6х=42
х=42:6
х=7