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olya8850
@olya8850
October 2021
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Как доказать, что 12^8*9^12 делиться на 6^12. Очень нужно
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sedinalana
Verified answer
(2²*3)^8*(3²)^12/(2*3)^12=2^16*3^8*3^24/(2^12*3^12)=
=2^16*3^32/(2^12*3^12)=2^4*3^20
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(2²*3)^8*(3²)^12/(2*3)^12=2^16*3^8*3^24/(2^12*3^12)==2^16*3^32/(2^12*3^12)=2^4*3^20