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TeamWean
@TeamWean
September 2021
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Как это получилось????????
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армения20171
S(0,2*0,5^xdx=S2/10 *(5/10)^xdx=
S(1/5 *(1/2)^x)dx=S1/5 *(2^-1)^xdx=
S(2^(-x)/5 )*dx=1/5 *S(2^(-x)dx=
-1/5* S(2^(-x)*d(-x)=-1/5 *2^(-x)/ln2 +C=
-2^(-x)/(5ln2)+C
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Answers & Comments
S(1/5 *(1/2)^x)dx=S1/5 *(2^-1)^xdx=
S(2^(-x)/5 )*dx=1/5 *S(2^(-x)dx=
-1/5* S(2^(-x)*d(-x)=-1/5 *2^(-x)/ln2 +C=
-2^(-x)/(5ln2)+C