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July 2022
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Как найти Ymax и Ymin:y= -x^2+x+6
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ShirokovP
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Так ветви направлены вниз, то максимум будет в вершине параболы, в точке x0 = - b/2a = 1/2
ymax = y ( 1/2) = - ( 1/2)^2 + 1/2 + 6 = - 1/4 + 1/2 + 6 = 6,25
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Verified answer
Так ветви направлены вниз, то максимум будет в вершине параболы, в точке x0 = - b/2a = 1/2ymax = y ( 1/2) = - ( 1/2)^2 + 1/2 + 6 = - 1/4 + 1/2 + 6 = 6,25