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Jane610
@Jane610
July 2022
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Как решить 3-ю задачу?
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komandor57
M(Co2)=6,6г. n(Co2)=m/M=6,6:(12+32)=0,15моль
n(C)=0,15моль
m(H2O)=5,4г n(H2O)=5,4г/18=0,3моль
n(H)=0,3*2=0,6моль
n(C):n(H)=0,15:0,6=1:4
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Answers & Comments
n(C)=0,15моль
m(H2O)=5,4г n(H2O)=5,4г/18=0,3моль
n(H)=0,3*2=0,6моль
n(C):n(H)=0,15:0,6=1:4
CH4
Метан