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хвостиком
@хвостиком
July 2022
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как решить: 8x^2-3*(x-4)=12
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11nasta00
Обычное кв уравнение , 8х^2-3х+12=12 8x^2-3x=0 x(8x-3)=0 x=0 или 8х-3=0 8х=-3
х=-3\8=-0,375
6 votes
Thanks 5
mkim97
8x^2 - 3(x-4)= 12
8x^2 - 3x + 12 = 12
8x^2 - 3x = 0
x(8x - 3) = 0
x=0
8x = 3
x = +- 0.375
4 votes
Thanks 4
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Answers & Comments
х=-3\8=-0,375
8x^2 - 3x + 12 = 12
8x^2 - 3x = 0
x(8x - 3) = 0
x=0
8x = 3
x = +- 0.375