как решить а) (х - 1)(х - 3) = (х - 2)(х + 3); б) (2y - 1)(1 - y) + (y + 1)(2y - 3) = 0; в) (0,5х - 3,5)(6х + 2) + 30х = 3х(х - 3) - 26;
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-4x+3=x-6
-5x=-9
x=9/5
б) 2y-2y^2-1+y+2y^2-3y+2y-3=0
2y-4=0
2y=4
y=2
в) 3x^2+x-21x-7+30x=3x^2-9x-26
10x-7=-9x-26
19x=-19
x=-1