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haizenberg06
@haizenberg06
July 2022
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Как решить уравнение ? x(x-2)(x+1)=x^2(x-1). ?
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Devil2031
X^3-2x^2+x^2=x^3-x^2
-2x=0
x=0
0 votes
Thanks 1
tlegenova1973
(х^2-2х)(х^2+1)=х^3-х^2
х^2-2х+х^2+1-х^3+х^2
-х^3+3х^2-2х+1=0
х^3-3х^2+2х-1=0
х(х^2-3х+2)-1=0
х-1=0. х^2-3х+2=0
х=1. Д=В2-4ас=9-4*2=1
х1=3-1/2=1. х2=3+1/2=2
0 votes
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Answers & Comments
-2x=0
x=0
х^2-2х+х^2+1-х^3+х^2
-х^3+3х^2-2х+1=0
х^3-3х^2+2х-1=0
х(х^2-3х+2)-1=0
х-1=0. х^2-3х+2=0
х=1. Д=В2-4ас=9-4*2=1
х1=3-1/2=1. х2=3+1/2=2