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Yanochka1112
@Yanochka1112
June 2022
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какая масса оксида фосфора (v) образуется при сгорании 62 г фосфора???
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Pegs
4P + 5O2 --> 2P2O5
n (P) = 62/31 = 2 моль
n (P) : n (P2O5) = 2 : 1 => n (P2O5) = 1 моль
m (P2O5) = 142 (Mr P2O5) * 1 = 142 г
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Answers & Comments
n (P) = 62/31 = 2 моль
n (P) : n (P2O5) = 2 : 1 => n (P2O5) = 1 моль
m (P2O5) = 142 (Mr P2O5) * 1 = 142 г