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nosovavalera
@nosovavalera
September 2021
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Какая масса серной кислоты потребуется для полного растворения 12 г магния?
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twixer98
4Mg + 5H2SO4 = 4MgSO4 + H2S + 4H2O
n(Mg) = 12/24 =0.5
n(H2SO4) = 0.5*5/4 = 0.625
m(H2SO4) = 0.625*98 = 61.25(гр)
6 votes
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nosovavalera
спасибо огромное!)
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Answers & Comments
n(Mg) = 12/24 =0.5
n(H2SO4) = 0.5*5/4 = 0.625
m(H2SO4) = 0.625*98 = 61.25(гр)