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Nicolleta
@Nicolleta
April 2021
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какая масса спирта может быть получена при гидратации этилена обьёмом 448л
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udodovi
448л хг
C2H4+H2O=C2H5OH
22,4л 46г
х= 448*46/22,4=920г
1 votes
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Answers & Comments
C2H4+H2O=C2H5OH
22,4л 46г
х= 448*46/22,4=920г