Mr(CaF2) = 40 + 19*2 = 78
W(F) = Ar(F) * n / Mr(CaF2) * 100% = 19*2 / 78 *100% = 49%
Mr(Na2AlF6) = 23*2 + 27 + 19*6 =187
W(F) = Ar(F) * n / Mr(Na2AlF6) *100% = 19*6 / 187 *100% =61%
богаче фтором Na2AlF6
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Verified answer
Mr(CaF2) = 40 + 19*2 = 78
W(F) = Ar(F) * n / Mr(CaF2) * 100% = 19*2 / 78 *100% = 49%
Mr(Na2AlF6) = 23*2 + 27 + 19*6 =187
W(F) = Ar(F) * n / Mr(Na2AlF6) *100% = 19*6 / 187 *100% =61%
богаче фтором Na2AlF6
W(F)=19*2/78*100=48.7%
M(Na2ALF6)=187 g/mol
W(F)=19*6187*100%=61%
в Na2ALF6 больше фтора