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dashuta11
@dashuta11
July 2022
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Какое кол-во вещества Н2 прореагировало с Сl ,если V (H2)=16 литров?
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jansulu799
Verified answer
H2+Cl2=2HCl
n(H2)= V(H2)/Vm=16 л/22,4 л/моль=0,714 моль
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mrvladimir2
Verified answer
Дано:
V(H2) = 16 л
Найти:
n(H2)=?
n(H2)=V(H2)/Vm = 16 л/ 22,4 л/моль = 0,714 моль
0 votes
Thanks 0
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Answers & Comments
Verified answer
H2+Cl2=2HCln(H2)= V(H2)/Vm=16 л/22,4 л/моль=0,714 моль
Verified answer
Дано:V(H2) = 16 л
Найти:
n(H2)=?
n(H2)=V(H2)/Vm = 16 л/ 22,4 л/моль = 0,714 моль