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pavel256pavel
@pavel256pavel
July 2022
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какое количество холодной воды имеющей температуру 10 надо добавить в кастрюлю чтобы охладить 2 л воды от 80 до 50
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wkw
Q=cm(t2-tсмеси)
m=ρ*V
m=1000кг/м3*0,002м3=2кг
Q=4200Дж/кгС*2 кг(80С-50С)=252000Дж
m=Q/c(tсмеси-t1)
m=252000Дж/4200(50С-10С)=1,5 кг
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Answers & Comments
m=ρ*V
m=1000кг/м3*0,002м3=2кг
Q=4200Дж/кгС*2 кг(80С-50С)=252000Дж
m=Q/c(tсмеси-t1)
m=252000Дж/4200(50С-10С)=1,5 кг