Q ( нагревания ) = сm (t2-t1)
Q = 2,4 * 10³ * 3 * ( 51 - 24 ) = 7,2 * 10³ * 27 = 194,4 * 10³ = 194400 Дж
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Q ( нагревания ) = сm (t2-t1)
Q = 2,4 * 10³ * 3 * ( 51 - 24 ) = 7,2 * 10³ * 27 = 194,4 * 10³ = 194400 Дж