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lender825
@lender825
August 2022
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Какое количество теплоты выделится при кристаллизации 200г воды при температуре 0 градусов?
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walesofficial
Q=Jводы*mводы
Jводы=330000
Q=330000*0.2=66000Дж
2 votes
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Jводы=330000
Q=330000*0.2=66000Дж