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serdukmashenka
@serdukmashenka
August 2021
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какое количество вещества содержится в оксиде фосфора массой 28,4 грамма?
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vladgushchin9
N(P2O5)=
=
=0,2moль
N=Na*n=6,02*
*0,2moль=1,204*
моль
2 votes
Thanks 5
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N=Na*n=6,02**0,2moль=1,204*моль