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МАЛИКА228
@МАЛИКА228
July 2022
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Какое количество вещества составляет 25 грамм карбоната кальция ( Ca C O3)?
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Platinum15
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M(CaCO3) = 100 г/моль
n(CaCO3) = 25/100 = 0.25 моль
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Verified answer
M(CaCO3) = 100 г/мольn(CaCO3) = 25/100 = 0.25 моль