Mr(Fe2O3) = 160
W (Fe) = 112 ÷ 160 × 100% = 70%
Mr(FeCl2) = 127
W(Fe) = 56 ÷ 127 × 100% = 44,1%
Ответ: Fe2O3
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Mr(Fe2O3) = 160
W (Fe) = 112 ÷ 160 × 100% = 70%
Mr(FeCl2) = 127
W(Fe) = 56 ÷ 127 × 100% = 44,1%
Ответ: Fe2O3