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cccp228
@cccp228
June 2022
2
9
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Какое значение получит переменная у после выполнения фрагмента алгоритма?
х:=1
у:=2*х
у:=у+3
у:=у*х
у:=у+4
у:=у*х
у:=у+5
Восстановите формулу вычисления у для произвольного значения x
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Answers & Comments
APALoff
1)x=1
2)y=2*1=2
3)y=2+3=5
4)y=5*1=5
5)y=5+4=9
6)y=9*1=9
7)y=9+5=14
Ответ: 14
y(x)=
((2*x+3)*x+4)*x+5
42 votes
Thanks 72
Gleb1Kosyrev
Verified answer
Ответ: 14
обоснование:
Var x,y : Integer;
Begin
x:=1;
y:=2*x;
y:=y+3;
y:=y*x;
y:=y+4;
y:=y*x;
y:=y+5;
Writeln(y);
end.
Общая формула вычисления: ((2*x+3)*x+4)*x+5
138 votes
Thanks 314
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Answers & Comments
2)y=2*1=2
3)y=2+3=5
4)y=5*1=5
5)y=5+4=9
6)y=9*1=9
7)y=9+5=14
Ответ: 14
y(x)=((2*x+3)*x+4)*x+5
Verified answer
Ответ: 14обоснование:
Var x,y : Integer;
Begin
x:=1;
y:=2*x;
y:=y+3;
y:=y*x;
y:=y+4;
y:=y*x;
y:=y+5;
Writeln(y);
end.
Общая формула вычисления: ((2*x+3)*x+4)*x+5